SOLVE: Isomorphism Problem for Z252 X Z294 and Z42 X Z1764

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Homework Statement


is Z252 X Z294 isomorphic to Z42 X Z1764? Explain.


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The Attempt at a Solution


I checked that the highest order of the element in both group are 1764, but don't really know how to justify if there is an isomorphism...Can anyone give me some hints?
 
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Hi phyalan! :smile:

Let's first write your thingies in a more canonical form. For this I want you to take the prime decomposition of 252, 294, 42, 1764 and apply the following formula:

\mathbb{Z}_{ab}\cong \mathbb{Z}_a\times \mathbb{Z}_b

if gcd(a,b)=1.

For example, you could write

\mathbb{Z}_{84}\cong \mathbb{Z}_4\times\mathbb{Z}_3\times \mathbb{Z}_7.

Try to do this with your groups...
 
So is
\mathbb{Z}_a\times \mathbb{Z}_b\cong \mathbb{Z}_b\times \mathbb{Z}_a ?

if that's ok, then i m done.
Anyway, thank you micromass =)
 
Yes, that's true! :smile:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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