Solve Kinematic Problem: Ball Falls 1.52m from Table

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The problem involves a ball falling from a table 1.2 meters high and landing 1.52 meters horizontally away. To determine the time it takes for the ball to hit the ground, the vertical motion can be analyzed using the height and gravitational acceleration. The initial horizontal velocity can then be calculated using the horizontal distance traveled and the time of flight. It is clarified that the initial velocity is considered to be purely horizontal, simplifying the calculations. Understanding these parameters is crucial for solving the kinematic equations related to the ball's motion.
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A ball moves to the edge of a table which is 1.2 m above ground. The ball falls off and hits the ground 1.52 m horizontly from the edge of the table.

(a) How much time does it take the ball to hit the ground?
(b) What's the ball initial velocity?

Am I to understand that the initial velocity is only horizontly (Vo,x)? Because if it's not I don't know its size, the angle it creates with the horizon and the time factor... 3 variables with 2 equations...
 
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Yes, assume the initial velocity is horizontal.
 
thanks!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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