Solve Kinematics Problem: Autographed Baseball Falling Off Desk

AI Thread Summary
An autographed baseball falls from a 1.2 m high desk and lands 0.41 m away, with gravity at 9.81 m/s². To solve for the initial velocity, the time of fall must first be calculated using the equation d = 0.5gt². After determining the time, the horizontal velocity can be found using v = d/t, where d is the horizontal distance. This method is applicable to similar problems with different values. Understanding the relationship between time, distance, and acceleration is crucial for solving kinematics problems effectively.
hypoovenmitts
Messages
2
Reaction score
0

Homework Statement



An autographed baseball rolls off of a 1.2 m high desk and strikes the floor 0.41 m away from the desk. The acceleration of gravity is 9.81 m/s2 . How fast was it rolling on the desk before it fell off?
Answer in units of m/s.

Homework Equations



You might need to use
v^2=vi^2 + 2a(x-xi)
although I'm not really sure. :/

The Attempt at a Solution



I'm not sure how to solve this when you're not given the velocity :( I just need someone to explain how to do this, because there's 3 problems on my homework exactly like it but with different numbers. Thank you~
 
Physics news on Phys.org
hypoovenmitts said:

Homework Equations



You might need to use
v^2=vi^2 + 2a(x-xi)
although I'm not really sure. :/
There are more equations than just that one for kinematics problems. Find an equation that involves time, which you can solve for. Figuring out how long it takes the ball to hit the floor will be a big first step in solving this problem.

The Attempt at a Solution



I'm not sure how to solve this when you're not given the velocity :( I just need someone to explain how to do this, because there's 3 problems on my homework exactly like it but with different numbers. Thank you~
 
hi ,

first, i try to get the t from the free fall equation d=.5gt^2, given d=1.2m and g=9.81 m/sec/sec. Once i get the t, i use this on the equation v = d/t, d = 0.41m and t from the first part.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top