Solve Linear Expansion Problem at 35ºC | AP Physics 2

Click For Summary

Discussion Overview

The discussion revolves around a linear expansion problem involving a uniform rod, specifically how to calculate its length change when the temperature increases from 5ºC to 35ºC. Participants are exploring the concept of linear expansion in the context of AP Physics 2, focusing on the coefficient of linear expansion and its implications in calculations.

Discussion Character

  • Homework-related, Mathematical reasoning, Technical explanation

Main Points Raised

  • One participant presents a linear expansion problem and seeks the procedure for solving it, indicating that they are reviewing the topic for practice.
  • Another participant clarifies that K^-1 indicates a change of 5.0 × 10^-4 per change in Kelvin, suggesting an understanding of the coefficient's meaning.
  • A later reply reiterates the previous point about K^-1, indicating some confusion about its interpretation, but ultimately confirms the understanding after receiving clarification.
  • One participant provides the equation for linear expansion, detailing the variables involved and their units, while also mentioning a related concept of volume expansion.

Areas of Agreement / Disagreement

There is no explicit consensus on the procedure for solving the problem, as participants are still discussing the interpretation of the coefficient and the application of the equation. Some confusion exists regarding the units and their implications.

Contextual Notes

Participants have not fully resolved the mathematical steps involved in applying the linear expansion equation, and there may be assumptions regarding the temperature change and its measurement that are not explicitly stated.

Who May Find This Useful

Students studying thermal expansion concepts in physics, particularly those preparing for AP Physics exams or similar coursework.

Wei
Messages
2
Reaction score
0
A uniform rod of a length of 2.0 m at 5ºC has a coefficient of linear expansion of 5.0 × 10^-4 K^-1. How much longer is it when the temperature is 35ºC?

I want to know the procedure to solve this problem

This isn't hw, but I'm wondering how to solve it when it's K ^-1
Just trying to get some practice.
Currently taking AP Physics 2; Passed this topic last semester and reviewing
 
Last edited:
Science news on Phys.org
I think K-1 just means 1/K, meaning that it's a change of 5.0x10-4 per change in kelvin.
 
  • Like
Likes   Reactions: Wei
Drakkith said:
I think K-1 just means 1/K, meaning that it's a change of 5.0x10-4 per change in kelvin.
Oh that's what it means? Since it was K^-1 I just assumed that it was 1/5.0x10^-4 K
Ok Thanks!
 
here is the equation for linear expansion.
L=Li+Li*k*change in tempature, units are L=length after tempature change in celsius or kelvin, Li=length before tempature change, k=constant that is the linear expanison coefiicient units are 1/k or 1/c, tempature=measured in celsius or kelvin.
by the way for volume expansion just multiply the linear expansion by 3.
this equation could be very helpful if you have a chart of the linear expansion coefficients.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 13 ·
Replies
13
Views
21K