Solve Logarithm Math Problem: LOG3(X+3)+LOG3(X-1)=1

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The math problem LOG3(X+3) + LOG3(X-1) = 1 simplifies to LOG3((X+3)(X-1)) = 1, leading to the equation 3^1 = (X^2 + 2X - 3). The quadratic equation 0 = (X^2 + 2X - 6) is derived, and the roots are found using the quadratic formula. However, it is crucial to check which root is valid since logarithms are not defined for negative numbers. The positive root, {-2 + √28}/2, is confirmed as the solution for the original equation.
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Homework Statement


NEED HELP WITH THIS MATH PROBLEM: LOG3(X+3) + LOG3(X-1) = 1

Homework Equations


The Attempt at a Solution


I SAID LOG3(X+3) + LOG3 (X-1)
SIMPLIFIES TO LOG3(X+3)*(X-1) = 1
I.E LOG3(X^2 +2X - 3) = 1
THEN 3^1 = (X^2 +2X - 3)
AND 0 = (X^2 +2X - 6)
THEN USE THE QUADRATIC FORMULA TO FIND X AS {-2+/- 28^1/2}/2
JUST NEED A SECOND OPINION TO SEE IF ITS CORRECT.
 
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The calculation is correct so far, but you have to investigate what root is solution of the original equation. Hint: is logarithm defined for negative numbers? ehild
 
ehild said:
the calculation is correct so far, but you have to investigate what root is solution of the original equation. Hint: Is logarithm defined for negative numbers?


Ehild
ok so logarithms are not defined by negative values hence the root for the original equation would have to be the positive value of x which would have been {-2 +[28^1/2]}/2 is that the final solution.
 
Correct for the real logarithmic function.

(Later you will learn about complex numbers and functions, and the complex logarithm is defined for negative numbers, too. )

ehild
 
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