Solve Mass & Energy Homework: Find Max Stretch & Amplitude

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The discussion revolves around solving a physics homework problem involving a mass on a vertical spring. The user is struggling to calculate the maximum stretch of the spring after the mass falls, despite having already solved for the amplitude of vibration. Key points include the use of conservation of energy principles and the distinction between equilibrium and oscillation states. Participants emphasize that the maximum stretch occurs during oscillation, not at equilibrium. The conversation highlights the importance of understanding energy transformations in the system.
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Homework Statement


Hello, I'm having an issue with a question I have all the numbers and everything but I can't quite get the answer correctly and its very frustrating..

A mass, m is held at UEP of a vertical spring constant k & allowed to fall. Calculate:
a) The maximum stretch(max bottom)
b) The amplitude of vibration

Homework Equations


PEg + PEe + KE= PEg' +PEe'+ KE'
h = xo = mg/k

The Attempt at a Solution


I've solved the amplitude of vibration already I am just stuck at part a) I really do not know how start please help thanks
 
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You've quoted the right equations - just fill in the blanks: in terms of the desired unknown, what are the loss in gravitational PE, the gain in spring PE, and the change in KE?
 
about maximum stretch
I'm not sure but I think I think that depends on the spring ,,
If it is in equilibrium after falling we will use the laws of conservation of energy ,
If it is not "say it is oscillating" we shall use Newton second law , because in oscillation , we can't specify the final and initial positions of the string [it would go back farther than it's initial position when it's allowed to fall]

I'm I right ??
 
Maged Saeed said:
about maximum stretch
I'm not sure but I think I think that depends on the spring ,,
If it is in equilibrium after falling we will use the laws of conservation of energy ,
If it is not "say it is oscillating" we shall use Newton second law , because in oscillation , we can't specify the final and initial positions of the string [it would go back farther than it's initial position when it's allowed to fall]

I'm I right ??
No, it's not the stretch at equilibrium we want, it's the maximum stretch, and that occurs once in each oscillation.
 

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