Solve Momentum Problem: Ball 1, Ball 2, Ball 3 | Magnitudes 2 & 6.928

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The discussion revolves around solving a momentum problem involving three balls with specified magnitudes. The final calculated velocities for the balls are Ball 1: <-2, 0>, Ball 2: <6, 3.46>, and Ball 3: <6, -3.46>, with magnitudes of 2 and 6.928. There is a concern regarding the first ball's backward motion, which seems counterintuitive. The importance of practical experience, such as spending time at a billiard table, is emphasized for better understanding of physics concepts. Overall, the calculations appear correct, but the intuitive understanding of momentum raises questions.
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For my final answers I got:
Ball 1:< -2 , 0 >
Ball 2:< 6 , 3.46 >
Ball 3:< 6 , -3.46>

With magnitudes of 2 and 6.928 respectively. I feel like I did the problem correct, and the equations work out right, but intuitively I feel that the first ball shouldn't bounce backwards, but instead continue forward.
 
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Spend more time at the billiard table. It's very instructive. It's real physics!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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