- #1
Benjamin_harsh
- 211
- 5
- Homework Statement
- (n-2)180
- Relevant Equations
- (n-2)180
In the video, I didn't understand (n-2)180 part @5:33. Please explain.
Solve n-2)180: Video Explanation Requested
- Thread starter Benjamin_harsh
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AI Thread Summary
The discussion centers on the formula for calculating the sum of the interior angles of an n-sided polygon, expressed as (n-2)180 degrees. Participants clarify that this formula applies to both regular and irregular polygons. A link to a Khan Academy resource is provided for further explanation, emphasizing the formula's relevance. The conversation highlights the importance of understanding this geometric principle in relation to polygons. Overall, the thread aims to clarify the concept of polygon angle sums.
Neglect gravity other than that of water; neglect friction.
F1=ρgsh=1000*10*1*(1+4)=50000 N;
F1=ρgsh=1000*10*0.1*4=4000 N;
F3=50000-4000=46000 N?
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system
$$M(t) = M_{C} + m(t)$$
$$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$
$$P_i = Mv + u \, dm$$
$$P_f = (M + dm)(v + dv)$$
$$\Delta P = M \, dv + (v - u) \, dm$$
$$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$
$$F = u \frac{dm}{dt} = \rho A u^2$$
from conservation of momentum , the cannon recoils with the same force which it applies.
$$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook.
Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water.
I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
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