Solve Negative/Positive Homework: Momentum-Impulse Theorem

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SUMMARY

The discussion centers on the application of the Momentum-Impulse Theorem to calculate the average force exerted by a bullet on a bulletproof vest. A 6.00g bullet traveling at 100m/s comes to rest in 600 microseconds, leading to an initial calculation of -1.00kN for the force. The negative sign indicates the force opposes the bullet's motion, but the correct interpretation is that the force imparted to the wearer is +1.00kN, aligning with the positive direction of the bullet's initial velocity. The textbook's answer of -1.00kN is incorrect based on this reasoning.

PREREQUISITES
  • Understanding of the Momentum-Impulse Theorem
  • Basic knowledge of force calculations in physics
  • Familiarity with units of mass and velocity (grams, meters per second)
  • Concept of directionality in vector forces
NEXT STEPS
  • Review the Momentum-Impulse Theorem in detail
  • Study examples of force calculations involving momentum changes
  • Learn about vector forces and their directionality in physics
  • Examine common misconceptions in physics problems related to force directions
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of momentum and force interactions in collision scenarios.

gold123456th
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Homework Statement


Suppose a 6.00g bullet traveling at 100m/s strikes a bulletproof vest and comes to rest in about 600microseconds. What average force will it impart to the happy wearer?


Homework Equations


Use the Momentum-Impulse Theorem
I took the initial direction of the bullet as the positive direction.

The Attempt at a Solution


By using the momenum-impulse theorem, where vi = 100m/s and vf = 0m/s, I calculated the force to be -1.00kN. However, the negative sign tell me that this force is against the bullet, which should be the force that the vest apply to stop the bullet, not the force the bullet imparted to the wearer. The force that the bullet will impart on the wearer should be in the positive direction, which is the initial direction of the bullet. Therefore, I think the average force that the bullet imparted to the wearer should be +1.00kN. Nevertheless, the answer in the textbook for this question is -1.00kN, so I don't know whose right, the textbook or me.
 
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I would say you were right.
If you take the direction of the bullet to be +ve then the force obviously acts in that direction on the victim.
 

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