Solve Normal Stress Problem: Width of 30kN Offset Link, 73MPa Max

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Homework Help Overview

The problem involves determining the required width of an offset link that supports a load of 30 kN, with a constraint that the combined normal stress must not exceed 73 MPa. The link has a rectangular cross-section with a specified thickness of 40 mm.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various methods attempted to solve for the width, including the use of shear stress formulas and normal stress calculations. There is confusion regarding the appropriate stress type to consider for the problem.

Discussion Status

Participants are actively engaging with the problem, with some expressing frustration over their attempts. Guidance has been offered regarding the focus on normal stress rather than shear stress, indicating a productive direction in the discussion.

Contextual Notes

There is a mention of a figure that is not yet visible, which may be crucial for understanding the problem setup. Participants are also navigating the distinction between normal and shear stress in their approaches.

ashleyw6
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Homework Statement



An offset link supports a load of 30 kN as shown in figure 6. Determine its required width w if the total (combined) normal stress is not to exceed 73 MPa?

The cross section of the link is rectangular and has thickness of 40 mm

Homework Equations



stress= N/A

I have tried many different ways to solve this problem but end up hitting a wall! any help would be greatly appreciated :)
 

Attachments

  • Figure 6.JPG
    Figure 6.JPG
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Last edited:
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hi ashley, welcome to pf

can't see the pic yet, they usually take a while to claar, what have you tried?
 
Hi lanedance,

I have tried using the shearforce formula: [tex]\tau=VQ/It[/tex] but am unable to get any where...
 
without being able to see the pic... why are you finding shear stress? when you want to find normal stress (Force/Area)
 
wow how dumb do i look :P i have tried solving the question in every way i could think of but i am doing something wrong. I have used the normal shear formula but again to no avail.
Thanks for the help!
 

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