Solve Oscillation Problems: Find Mass m with Frequency Change

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A mass at the end of a spring oscillates at 0.83 Hz, and adding an additional 680-g mass reduces the frequency to 0.60 Hz. The calculations involve using the equations w = 2 pi f and w^2 = k / m to find the mass m. One participant calculated m to be approximately 0.74725 kg, while another found it to be around 0.744 kg, indicating close results. The method used involved finding the angular frequencies first and setting up a ratio to solve for m. The discussion highlights the importance of understanding oscillation frequency changes in relation to mass.
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Homework Statement



A mass m at the end of a spring oscillates with a frequency of 0.83 Hz. When an additional 680-g mass is added to m, the frequency is 0.60 Hz. What is the value of me?

Homework Equations



w = 2 pi f

w^2 = k / m

The Attempt at a Solution



m = .74725 kg

I'll probably be adding a few more problems, as my textbook didn't come with a solutions manual. I wish it did.
 
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Hmm.. I got 0.744kg.

Did you find w first and then sub it in with a rounded off value?

Or did you find m algebraically and then evaluate?
 
jaseh86 said:
Hmm.. I got 0.744kg.

Did you find w first and then sub it in with a rounded off value?

Or did you find m algebraically and then evaluate?

Our answers are close enough. It looks like I did it correctly.

I found the two "w"s first, expressed the masses in terms of m, setup a ratio and solved for m.
 

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