Solve Physics 11 Homework: Work to Slide Block on Shelf

  • Thread starter Thread starter roxxyroxx
  • Start date Start date
  • Tags Tags
    Physics Physics 11
AI Thread Summary
To calculate the work done sliding a 1.0 kg block along a shelf, the relevant formula is W = F x d, where W is work, F is the force applied, and d is the distance moved. The block is subjected to a kinetic friction force, which can be calculated using the coefficient of friction (0.23) and the normal force (equal to the weight of the block). The normal force is 9.81 N, resulting in a frictional force of approximately 2.25 N. Therefore, the work done sliding the block 1.5 m is W = 2.25 N x 1.5 m, equating to 3.4 J. Understanding the frictional force is crucial for accurately calculating the work done.
roxxyroxx
Messages
48
Reaction score
0

Homework Statement



A 1.0 kg block of wood is lifted a distance of 1.5 m from the floor and placed on a wooden shelf. A steady horizontal force is then applied to the block, causing it to slide sideways along the shelf a distance of 1.5 m at a uniform velocity. The kinetic coefficient of friction for the block when it is on the shelf is 0.23.
How much work is done sliding the block along the shelf?

Homework Equations



W = F x d

The Attempt at a Solution



Is there some formula I should be using?
I tried W = F x d but that doesn't give me the right answer of 3.4 J . Help?
 
Physics news on Phys.org
What are you using for F?
 
Thread 'Minimum mass of a block'

Thread 'Minimum mass of a block'

Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
View full post »

Thread 'Electric field due to charges between 2 parallel infinite planes'

TL;DR Summary: Find Electric field due to charges between 2 parallel infinite planes using Gauss law at any point Here's the diagram. We have a uniform p (rho) density of charges between 2 infinite planes in the cartesian coordinates system. I used a cube of thickness a that spans from z=-a/2 to z=a/2 as a Gaussian surface, each side of the cube has area A. I know that the field depends only on z since there is translational invariance in x and y directions because the planes are...
View full post »

Similar threads

How Much Work Does Kinetic Friction Do on a Sliding Block?
Replies
6
Views
4K
What is the displacement of a 3.0 kg block sliding down an inclined plane?
Replies
12
Views
2K
Calculating Distance Traveled by Cart with Sliding Block
Replies
9
Views
3K
Need help with finding thermal and Kinetic energy
Replies
20
Views
2K
Finding the time it takes for two stacked blocks to travel
Replies
18
Views
3K
First post: work and energy problem
Replies
5
Views
2K
A frictionless incline with a block sliding down it....
Replies
2
Views
3K
Fluid static problem with wooden block being pulled down
Replies
9
Views
2K
Calculate the work required to move the block
Replies
28
Views
4K
Work and energy for a lowered block
Replies
5
Views
1K

Hot Threads

Recent Insights

Back
Top