Solve Physics HW: Find Net Force at t=2.00s

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To find the net force acting on a 3.00kg object at t=2.00s, the second derivatives of the position functions x=5(t^2)-1 and y=3(t^3)+2 are calculated, yielding an acceleration of (10, 36) m/s² at that time. Using the formula F=ma, the net force can be determined by multiplying the mass by the acceleration components. The discussion emphasizes the importance of correctly applying the second derivatives to find acceleration before calculating the force. Ultimately, the net force at t=2.00s can be derived from these calculations.
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Homework Statement


A 3.00kg object is moving in a plane, with its x and y coordinates given by x=5(t^2)-1 and y = 3(t^3) + 2, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t=2.00s


Homework Equations


F=ma


The Attempt at a Solution


i know i need to find the 2nd derivatives of the functions but i don't know if I am doing that right. i got 10 and 18t? I am not sure what to do with them though.
 
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hi scirfy! welcome to pf! :smile:

(try using the X2 icon just above the Reply box :wink:)
scirfy said:
A 3.00kg object is moving in a plane, with its x and y coordinates given by x=5(t^2)-1 and y = 3(t^3) + 2, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t=2.00s
…
i know i need to find the 2nd derivatives of the functions but i don't know if I am doing that right. i got 10 and 18t? I am not sure what to do with them though.

that's correct, the acceleration is (10, 18t) at time t

now you need to find the acceleration at t = 2.00, and then use F = ma to find the force :smile:
 

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