Solve Predicate Logic Homework Equations

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SUMMARY

The discussion centers on solving predicate logic equations involving real numbers. The first statement, (∀xεℝ)((x≠0)→((∃yεℝ)(xy=1)), is confirmed as true, indicating that for every non-zero real number, there exists another real number whose product is 1. The second statement, (∃yεℝ)(∀xεℝ)((x≠0)→(xy=1)), is deemed false, as it suggests the existence of a single real number y that satisfies the equation for all non-zero real numbers x, which is not possible.

PREREQUISITES
  • Understanding of predicate logic notation, specifically ∀ (for all) and ∃ (there exists).
  • Familiarity with implications in logical statements (→).
  • Basic knowledge of real numbers and their properties.
  • Experience with logical proofs and truth evaluation in mathematics.
NEXT STEPS
  • Study the principles of predicate logic and its applications in mathematical proofs.
  • Learn about the properties of real numbers and their implications in logic.
  • Explore examples of true and false statements in predicate logic.
  • Practice solving more complex predicate logic equations to enhance understanding.
USEFUL FOR

Students of mathematics, particularly those studying logic and proofs, as well as educators looking to clarify concepts in predicate logic.

.~!@#
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Homework Statement



1) (∀xεℝ)((x≠0)→((∃yεℝ)(xy=1)

2) (∃yεℝ)(∀xεℝ)((x≠0)→(xy=1))



Homework Equations



∃ - there exists
∀ - for all
→ implication

The Attempt at a Solution



The brackets and implication are throwing me for a loop

1) for all real numbers, there exist another real number such that their product is 1. TRUE

2) There exists a real number y, such that any real number and y will have a product of 1. False.

?
 
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.~!@# said:

Homework Statement



1) (∀xεℝ)((x≠0)→((∃yεℝ)(xy=1)

2) (∃yεℝ)(∀xεℝ)((x≠0)→(xy=1))

Homework Equations



∃ - there exists
∀ - for all
→ implication

The Attempt at a Solution



The brackets and implication are throwing me for a loop

1) for all real numbers, there exist another real number such that their product is 1. TRUE

2) There exists a real number y, such that any real number and y will have a product of 1. False.

?
Hello .~!@# !

What's the question?

Do you want to know if your answers are correct, or do you want your translation into English checked ? ... or what??
 
both
 

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