Solve Summation Problem: Const=b*∑i2yi+∑f(I)f(y)...

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Homework Statement


I have an equation in the general form:
const=b*∑i2yi+∑f(I)f(y)...)
where const,b are known constants.I have a general question.Is it possible from equations like this to identify how the ys should be distributes so as the const takes a specific value, e.g const=0.05? What I thought of doing was to assume that const is a radius of convergence but the sums are finite (n=20000 at most). A few general pointers would be greatly appreciated or if this is even solvable.
 
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Your question is really unclear.
 
clarification

OK let me try and explain it a little better. I know that const takes a specific value, i.e. const=0.05. I need to find what the "arrangement" of yis must be for this to happen. Think of it as follows: If y are a set of data values in what order should these values appear for the right part of the equation to converge to 0.05(what their distribution should be)?Is it even possible to do sth like this?
 
lilly92 said:
OK let me try and explain it a little better. I know that const takes a specific value, i.e. const=0.05. I need to find what the "arrangement" of yis must be for this to happen. Think of it as follows: If y are a set of data values in what order should these values appear for the right part of the equation to converge to 0.05(what their distribution should be)?Is it even possible to do sth like this?

Do you have an equation of the form
0.05 = b \sum_{i=1}^n i^2 y_i + \sum_{i=1}^n f(i) g_i(y_1,y_2, \ldots, y_n)
with known functions #f# and ##g_i##? That SEEMS to be what you are asking, but in very poor notation. If you mean something else, please try first to put it in good notation and not to leave out important information.
 
Yes, that's what I mean. I apologise.I didn't think the exact equation was necessary because I'm looking for some general pointers or even a yes-or-no answer if what I'm trying to do can be done. Thank you for your time.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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