Solve Thin-Lens Equation: Prove u=v, Find Focal Length Change

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To prove that an object at twice the focal length from a converging lens results in an image of the same size, the algebraic method shows that u equals v when using the thin lens equation. For a convex lens with a focal length of 5cm, moving from an object distance of 50cm to infinity requires calculating the image distances for both scenarios. The film must be positioned 50cm from the lens for the closest object, while for distant objects, the lens must be adjusted accordingly. Understanding the relationship between object distance, image distance, and focal length is crucial for solving these problems. This discussion emphasizes the application of the thin lens equation in practical scenarios.
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Question
i)
Prove that if an object is at a distance of twice the focal length from a converging lens, the image is the same size as the object. Show this using an algebraic method.

Possible Answer
Must prove u = v
2F = U
2/u + 2/v = u
u + v = 2u
v=u

ii)
A small hand-held camera has a convex lens with a focal length of 5cm. The camera is arranged so that by moving the lens in and out, objects from 50cm away to "infinity" (very remote objects like mountains and scenery) can be brought to an exact focus on the film. How many centimeters will the lens have to be moved as the focus is changed from the closest to the farthest object?

Possible Answer:
Well, F = 5cm
U = 50cm
No I can't do this, could someone explain it please.
 
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The solutions for both of these questions involve the thin lens equation. For (i) using the object distance and focal lenth will allow you to solve for the image distance. Then using a similar triangle argument you can show that the two heights are the same.

For (ii), find the image distances for each of the the two distances (50cm and infinity). Since objects at 50cm are the nearest objects that can be imaged, the flim must be located this far away from the lens... Hopefully this will start you along the right track.
 
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