Solve Using Conservation of Energy

AI Thread Summary
The problem involves a 50 kg spool and a 20 kg block, requiring the calculation of the distance the block must fall for the spool to achieve an angular velocity of 5 rad/s, as well as the tension in the cord. The conservation of energy principle is applied, equating potential energy lost by the block to the kinetic energy gained by both the block and the spool. The equations used include the relationship between linear and angular velocities and the moment of inertia of the spool. The discussion emphasizes solving for the distance fallen (h) and the tension in the cord (T) using the derived formulas. Ultimately, the focus is on applying energy conservation to find the required values.
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Homework Statement



Solve Using Conservation of Energy

The spool has a mas of 50 kg and a radius of gyration k(o) = .280m. If the 20 kg block A is released form rest, determine the distance the block must fall in order for the spool to have an angular velocity w = 5 rad/s. Also what is the tension in the cord while the block is in motion? Neglect the mass of the cord


Homework Equations





The Attempt at a Solution



T1 + V1 + T2 + V2

Does V1 = 0 because it is at rest from the start

T1 = .5mv2 + .5Iw2 = .5*20*0 + .5*50*.282 = 1.96

V2g = Wy (y is what I am looking for but how do i calculate work W)
V2e = .5ks2 = .5*.28*s2 = .14s2

T2 = .5*20*v2 + .5*50*.282 = 10v2 + 1.96

1.96 = Wy + .14s2 + 10v2 + 1.96



To answer the question "determine the distanc ethe block must fall" means solve for y right

To answer the question "what is the tension of the cord" means solve for s right

How do i find v
 
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The distance the block falls is your energy..

What does that go into?

m_b*g*h = 1/2*m_b*V2 + 1/2*m_s*R_s22

V = ω*R_s

So h is what you are solving for and I think that looks like ...

h = 1/2*ω2R_s2*(m_b + m_s)/(g*m_b)
 
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