Solve Vector Dynamics Problems with Initial and Final Velocity | 100 s

  • Thread starter Thread starter yardy_genius
  • Start date Start date
  • Tags Tags
    Dynamics Vector
AI Thread Summary
The discussion revolves around solving a vector dynamics problem involving an aircraft's initial and final velocities over a 100-second period. Key calculations include determining average velocity, average speed, constant acceleration, and the vertical height gained. There is confusion regarding the correct interpretation of the vertical component of the vectors, with participants debating whether the vertical axis should be represented by the j or k unit vector. The ambiguity in the problem allows for different interpretations of the axes, leading to varied conclusions about the vertical height. Ultimately, clarity on the coordinate system is essential for accurate problem-solving.
yardy_genius
Messages
13
Reaction score
0

Homework Statement



An air craft has an initial velocity of 90(i+ j)ms-1and a final velocity of 10(10i + 10j +3k) ms-1. The time taken for this change to occur is 100 s. Determine the:
a)average velocity for the 100 s period.
b)average speed for the period.
c)constant acceleration of the airplane in unit vector notation.
d)magnitude of the acceleration.
e)vertical height the plane has risen.
f)distance plane traveled for the 100 s period

Homework Equations





The Attempt at a Solution




I have calculated all the above but i am confused as to which one of the vectors to state as the variable.

using the formula S= ut + 0.5at^2

i got the unit vector form (9500i + 9500j+ 1500k) this is correct.

now the solution says the vertical height is 1500k, but i thought 9500j was the vertical component. can some please explain this to me.

my answer
 
Physics news on Phys.org
I think you must be picturing the x-y-z axes as representing, let's say, x for eastward, y for up (as in altitude), and z for northward? That could feasibly be true, but for the velocity here rising to 100i + 100j + 30k it would be more like a ride on fighter plane, gaining 100m in altitude for every 104m you travel over terrain. If you instead interpret z as representing altitude, then plane passengers will be less terrified. :smile:

I'm not saying I'm correct, but it seems the question does leave this up to you to decide. Which means there is room for ambiguity.
 
Last edited:
thanks, i was kinda thinking along those lines too...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top