Solve Water Slide Problem: Initial Speed 0.54m/s, Height 3.2m

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To solve the water slide problem, the initial speed is 0.54 m/s, and the height of the slide is 3.2 m. Conservation of energy can be applied to determine the final velocity at the bottom of the slide. The swimmer's splashdown location can be calculated by first finding the horizontal speed at a height of 1.5 m and then using kinematic equations to determine the time taken to fall that distance. The horizontal distance traveled can be found by multiplying the horizontal velocity by the time of flight. This approach effectively combines energy conservation and projectile motion principles.
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"If the height of the water slide is h = 3.2m and the person's initial speed at point A (at the top of slide) is 0.54m/s, at what location does the swimmer splash down in the pool?"

I need help with this guys. It may be relatively easy, but I'm not seeing it. I don't know what formula to apply here. I have an initial velocity and a height of the slide. Thanks in advance.
 
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Is that all the info given in the question? You can use conservation of energy to find the final velocity of the person, but from there I'm not sure what it is asking for.
 
It's asking for the distance from the end of the slide to the point where the swimmer splashes in the water.
 
How do I add an image?
 
In additional options, manage attachments. Well you know the Normal force will be 0 when the person is in the air about to splash.
 
This is a picture of the problem I'm having difficulty with. Thanks!
 

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Ok now with the picture is clearer, just find the speed at 1.5 m throught conservation of energy and then work it out with kinematics (uniform acceleration neglecting air drag)
 
The "projectile" is launched from 1.5m above the pool,
with a horizontal velocity.
 
After getting the horizontal speed, you have to find the time that it takes to fall 1.5m (h=(g*t^2)/2) then you find the horizontal distance that the kid went by x=vt.
 
  • #10
Cyclovenom said:
Ok now with the picture is clearer, just find the speed at 1.5 m throught conservation of energy and then work it out with kinematics (uniform acceleration neglecting air drag)

Would I use the formula v=square root of 2gh to figure out v2?
 
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