Solve Work Energy Power Homework with Friction Present

AI Thread Summary
The discussion focuses on understanding how to incorporate friction into calculations involving the work-energy theorem and conservation of energy. When an object moves up a ramp, the work done by friction should be added to the total work, while for downward movement, friction should be subtracted to find the net work done. The user expresses confusion about applying these principles in various scenarios, such as skiers and cars on slopes. They seek clarification on the correct equations to use when friction is present, highlighting the challenge of accounting for friction's opposing direction to displacement. Clear guidance on these concepts is essential for accurately solving related physics problems.
GrandMaster87
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Homework Statement


Hi Guys

I have a problem when working with conservation of energy and work energy theorem. I have a problem when friction is present in the system.

I don't know when to add the friction to get the total work done or when to minus the friction to find work done.

Will someone be able to help me out?

1. Let's say someone is going UP a ramb and friction is present.
2. a skier is going down a slope and friction is present along the course.
3. a person is going down a slope , friction present and they ask you to find the skiers velocity at the bottom.
4. a car is moving up a slope and friction is present and you need to work out the velocity at the top

My Answer.

When someone is going up a ramp we add the work done by friction to obtain the work done.

2. when someone is going down a ramp we minus the friction to find work done.

Im not to sure about this. In my exam i lost the 13 marks for this question. Can someone just maybe give me some equations to use when friction is present for the different situations because when friction is present i get really confused.

Thanks a lot for reading..looking forward to your replies
 
Physics news on Phys.org
Work done = F*d*cosθ.
Frictional always acts in the opposite direction to the displacement.
 
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