Solved: Probability of Achieving 6 in 24 Throws of 2 Dice

[sacuan]

Homework Statement

probability to achieve a couple of 6 launching a couple of dies for 24 times

Homework Equations

why i cannot calculate this as:
1/36 * (35/36)EXP23 * (24!/23!)

The Attempt at a Solution

it should be correct:
a="to achive a couple of 6 in 1 throw"
e="never achive a coule of 6 in 24 throws"
i can calculare p(a)=1/36
i can calculate p(e)=[1-p(a)]EXP24
so 1-p(e) should be my correct result

 

[radou]

Unless I'm missing something, it seems you can treat this like a Bernoulli scheme with the probability p = 1/36.

 

[sacuan]

i understand by myself

the exact text is of the problem is:

probability to achieve AT LEAST a couple of 6 launching a couple of dies for 24 times

so now i understand why i cannot use it

thank you