Solved: Relativistic Speed: Force of 30N Reaches 99% c in 7 x 10⁴ Sec

[neelakash]

Homework Statement

A particle of mass 1 gm starts from rest and moves under the action of a force of 30
Newtons defined in the rest frame. It will reach 99% the velocity of light in time
(a) 9.9 x 10³ sec (b) 7 x 10⁴ sec (c) 0.999 sec (d) 0.7 sec

Homework Equations

The Attempt at a Solution

I can safely disregard (c) and (d)

(a) can be found by kinematic calculation.But as the particle moves in relativistic speed, this classical calculation does not hold.

(b) looks correct to me.

But how to prove this?

Can anyone suggest anything?

 

[neelakash]

as speed increases,the value of m(v) also increases,thus reducing the acceleration.Thus, it takes longer time...In that respect (b) looks plausible.

 

[kdv]

Homework Statement

A particle of mass 1 gm starts from rest and moves under the action of a force of 30
Newtons defined in the rest frame. It will reach 99% the velocity of light in time
(a) 9.9 x 10³ sec (b) 7 x 10⁴ sec (c) 0.999 sec (d) 0.7 sec

Homework Equations

The Attempt at a Solution

I can safely disregard (c) and (d)

(a) can be found by kinematic calculation.But as the particle moves in relativistic speed, this classical calculation does not hold.

(b) looks correct to me.

But how to prove this?

Can anyone suggest anything?

In relativity, F = \frac{dp}{dt} still holds. For a constant force you have then

p_{final} - p_{initial} = F \Delta t

setting p initial equal to zero and using for the final p= \gamma m v gives the correct answer, which is indeed b.


Note: your argument is correct and it's sufficient if all you need is to pick the correct answer quickly from a choice of answers. I just wanted to show you how to do the calculation if you needed that at some point.

 

[neelakash]

Yes,I followed your argument.

Thanks for your help.

 

[neelakash]

Tell me one thing.The force is specified to be 30 dyne in its own rest frame.So, is the increase of mass is to be considered at all?