Solving 4x3 + 4y =0 and 4y3 + 4x =0: Explained!

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Homework Statement



how to solve this:

4x3 + 4y =0
4y3 + 4x =0


the solution is x = 0,1,-1
y = 0,-1,1

how did they bring such result :bugeye:
 
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rabihtawil said:

Homework Statement



how to solve this:

4x3 + 4y =0
4y3 + 4x =0


the solution is x = 0,1,-1
y = 0,-1,1

how did they bring such result :bugeye:

Find y from the first equation and then plug it into the second one so you're done!

AB
 
Altabeh said:
Find y from the first equation and then plug it into the second one so you're done!

AB

4x3 + 4y =0
x3 + y=0
y=x3

NOW... plugging in

4y3 + 4x =0
y3 + x=0
(x3)3 + x = 0

now what?? how do i continue from here :S
 
First, fix your algebra mistake. You dropped a sign. Once you fix that, you'll find you can factor the polynomial and solve for its roots.
 
vela said:
First, fix your algebra mistake. You dropped a sign.

4x3 + 4y =0
x3 + y=0
y=-x3

NOW... plugging in

4y3 + 4x =0
y3 + x=0
(-x3)3 + x = 0

vela said:
Once you fix that, you'll find you can factor the polynomial and solve for its roots.

Please i am stuck show me how, i know it should be factored by x but how?
 
Last edited:
First, simplify (-x3)3. What do you get?
 
vela said:
First, simplify (-x3)3. What do you get?

-x9 + x = 0

now what?
 
rabihtawil said:
-x9 + x = 0

now what?

-x9 + x = 0
x(-x8 + 1) = 0

x = 0 or x= 1 right?
 
You can flip the sign of the whole equation to make it a little simpler to work with:

x9-x=0

Now you have a common factor of x in both terms, so factor it out.

OK, you posted while I was writing. :) So you have

x(x8-1) = 0

So this means x=0 or x8-1=0, right? So you have one of the roots so far.

Note that x8-1=(x4)2-12 is a difference of squares, so what does it factor into?
 
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Thank you so much, very appreciated!
 
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