Chemistry Solving a Chemistry Equation: Question 10

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The discussion revolves around solving a chemistry equation related to atomic masses, specifically focusing on question 10 from a past exam paper. The user initially sets up an equation based on the total atomic mass of 571.5, leading to the equation 27x + 28.1y = 172. They seek guidance on deriving a second equation, suspecting it relates to the empirical formula. After receiving assistance, they calculate the values for x and y, ultimately finding x to be approximately 2.999. The conversation highlights the importance of understanding atomic mass and empirical formulas in solving chemistry problems.
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Homework Statement



http://www.xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9701%20-%20Chemistry/9701_s11_qp_12.pdf

question 10

Homework Equations



The Attempt at a Solution


The way I am doing it, is to get two equations in terms of x and y and then equate them. For the first equation I used the fact that all of the element's individual atomic masses will add up to 571.5. So i got 27x + 28.1y = 172
My problem now is how to get the second equation? I think it has something to do with the empirical formula, but I can't figure it out. Help!
 
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If you remove the Al and Si from the formula, what is the charge on the resulting ion?
 


What is 14.04% of 571.5?
 


Borek said:
What is 14.04% of 571.5?

I think I got it, thanks to you. So for x we find 14.17% of 571.5. That answer we divide by 27, (because we know that the mole of aluminium is 1), and the x i got is 2.999(pretty close to one of the options). Same for y. Thanks!
 
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