Solving a Collar's Angular Momentum Problem: Finding f(θ) and Max θ Reached

AI Thread Summary
The discussion revolves around solving a physics problem involving a collar on a rotating frame, focusing on finding the angular velocity function f(θ) and the maximum angle θ reached. Participants express uncertainty about using non-inertial frames and the forces acting on the collar, including gravitational force, normal force, and an external force. The maximum angle is determined by the equilibrium of forces, with the collar initially at rest at θ = 0. The conversation highlights the need to consider horizontal acceleration of the frame and the implications of treating it as a fictitious force. Understanding these concepts is crucial for accurately solving the problem.
harmyder
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Homework Statement


Initially collar is at rest with theta = 0. Find \dot\theta=f(\theta). And find maximum theta reached.

upload_2016-2-16_11-14-0.png


Homework Equations


I don't know if i allowed to use angular momentum about top-right frame corner as it's accelerating.

But i definitely will need second Newton law:)

The Attempt at a Solution


I know that there mg, N forces. But i can't figure out another force due to acceleration of the frame.
 
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Are you comfortable using non-inertial frames of reference?
 
haruspex said:
Are you comfortable using non-inertial frames of reference?

I think I'm not, but i believe there is no need in it here. Important thing is that i need to calculate θ' based on θ not on t.
 
harmyder said:
I think I'm not, but i believe there is no need in it here. Important thing is that i need to calculate θ' based on θ not on t.
It does help here, but it is never essential.
What force/acceleration equations can you write? It doesn't matter if you think they are wrong or incomplete, just post what you get.
 
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haruspex said:
It does help here, but it is never essential.
What force/acceleration equations can you write? It doesn't matter if you think they are wrong or incomplete, just post what you get.

The collar undergoes three forces - m\mathbf{g}, \mathbf{N}, \mathbf{F}_{ext}. From which |m\mathbf{g}|=|N|, though i can't prove it.

With angle \theta we have:
|m\mathbf{g}| acting downward and \big(|\mathbf{N}| + |\mathbf{F}_{ext}|\big)\cos\theta acting upward.

The maximum angle is reached with equilibrium.

And here i can't calculate the external force.
 
harmyder said:
The collar undergoes three forces - m\mathbf{g}, \mathbf{N}, \mathbf{F}_{ext}. From which |m\mathbf{g}|=|N|, though i can't prove it.

With angle \theta we have:
|m\mathbf{g}| acting downward and \big(|\mathbf{N}| + |\mathbf{F}_{ext}|\big)\cos\theta acting upward.

The maximum angle is reached with equilibrium.

And here i can't calculate the external force.
The external force acts on the frame, not on the collar.
Why do you think |mg|=|N|? Consider horizontal and vertical separately.
 
haruspex said:
It does help here, but it is never essential.
What force/acceleration equations can you write? It doesn't matter if you think they are wrong or incomplete, just post what you get.

I can't come up with solution in \hat{i}\times\hat{j} frame.
sliding_collar.png

Maybe i need to consider tangential parts of mg and anther force, i think this another force is ma? When they become equal, then no more change of angle.
 
The original post said "Initially collar is at rest with theta = 0" and according to the picture "theta= 0" is at the bottom! The collar won't move- \theta&#039;= 0. If you intended to the initial point to be at the top, with "theta" measured from the top, then, at each \theta, the downward acceleration vector, <0, -g>, can be written as the sum of two vectors, one parallel to the normal vector circular bar and one parallel to the tangent vector. Since the collar can't move normal to the bar, only the tangent vector is relevant.
 
HallsofIvy said:
The original post said "Initially collar is at rest with theta = 0" and according to the picture "theta= 0" is at the bottom! The collar won't move- \theta&#039;= 0.
Have you noticed rightward horizontal acceleration of the frame?
 
  • #10
harmyder said:
Maybe i need to consider tangential parts of mg and anther force, i think this another force is ma? When they become equal, then no more change of angle.
That is the non-inertial frame method I mentioned. You treat the acceleration as a 'fictitious' force ma acting the other way.
So what answer do you get?
 
  • #11
harmyder said:
Have you noticed rightward horizontal acceleration of the frame?
NO! I hadn't. Thanks.
 
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