Solving a Homework Equation: ΔV_H

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SUMMARY

The forum discussion centers on solving the homework equation for Hall voltage, represented as ΔV_H. The equation used is ΔV_H = IB / nqt, where the calculated electron density (n) is 1.28 x 10^29 electrons/m^3 based on provided values. Users are encouraged to verify calculations using WolframAlpha, and there is a mention of potential confusion regarding the measurement distance for Hall voltage, specifically whether to use 0.330 mm or 1 mm. The discussion concludes with a confirmation of the calculation's accuracy by a participant.

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  • Familiarity with the equation ΔV_H = IB / nqt
  • Basic knowledge of electron density calculations
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Homework Statement



OeP0E2B.png


Homework Equations





The Attempt at a Solution



$$Δ{ V }_{ H }=\frac { IB }{ nqt } \\ 9.6*{ 10 }^{ -6 }=\frac { 50*1.3 }{ n*e*3.3*{ 10 }^{ -4 } } \\ n=1.28*{ 10 }^{ 29 }\quad electrons/{ m }^{ 3 }$$
 
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mfb said:
You can use WolframAlpha to check calculations like that.

I thought the method was wrong because it gives us d=1mm but we don't use it in our calculations.
 
I'm not sure where the Hall voltage is measured, either 0.330mm or 1mm is not necessary.
 
Take a look at the Hyperphysics web page on the Hall Effect.

@Turion: Your calculation looks good.
 

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