Solving a Homework Equation: ΔV_H

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The discussion focuses on solving the equation for Hall voltage (ΔV_H) using the formula ΔV_H = IB/(nqt). The calculated value for electron density (n) is found to be 1.28 x 10^29 electrons/m^3. There is some confusion regarding the relevance of the distance measurement of 1mm in the calculations, with suggestions to refer to Hyperphysics for clarification on the Hall Effect. Overall, the calculations presented are deemed correct by one participant. The conversation emphasizes the importance of verifying calculations and understanding the parameters involved in the Hall Effect.
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Homework Statement



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Homework Equations





The Attempt at a Solution



$$Δ{ V }_{ H }=\frac { IB }{ nqt } \\ 9.6*{ 10 }^{ -6 }=\frac { 50*1.3 }{ n*e*3.3*{ 10 }^{ -4 } } \\ n=1.28*{ 10 }^{ 29 }\quad electrons/{ m }^{ 3 }$$
 
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mfb said:
You can use WolframAlpha to check calculations like that.

I thought the method was wrong because it gives us d=1mm but we don't use it in our calculations.
 
I'm not sure where the Hall voltage is measured, either 0.330mm or 1mm is not necessary.
 
Take a look at the Hyperphysics web page on the Hall Effect.

@Turion: Your calculation looks good.
 
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