Solving a Homework Equation: ΔV_H

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Homework Help Overview

The discussion revolves around a problem related to the Hall Effect, specifically focusing on the calculation of the Hall voltage (ΔV_H) and the associated electron density (n). Participants are examining the setup and assumptions involved in the calculations presented.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of ΔV_H and the derived electron density, questioning the relevance of certain parameters like the distance measurement in the context of the problem. There are also suggestions to verify calculations using external tools.

Discussion Status

Some participants have provided guidance on checking calculations and referenced external resources for further clarification. However, there are ongoing questions about the measurement setup and the necessity of specific values in the calculations, indicating a lack of consensus on certain aspects.

Contextual Notes

There is mention of potential confusion regarding the measurement distance for the Hall voltage, with participants noting different values that may or may not be relevant to the calculations. The original poster's approach to the problem is also under scrutiny.

Turion
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Homework Statement



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Homework Equations





The Attempt at a Solution



$$Δ{ V }_{ H }=\frac { IB }{ nqt } \\ 9.6*{ 10 }^{ -6 }=\frac { 50*1.3 }{ n*e*3.3*{ 10 }^{ -4 } } \\ n=1.28*{ 10 }^{ 29 }\quad electrons/{ m }^{ 3 }$$
 
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mfb said:
You can use WolframAlpha to check calculations like that.

I thought the method was wrong because it gives us d=1mm but we don't use it in our calculations.
 
I'm not sure where the Hall voltage is measured, either 0.330mm or 1mm is not necessary.
 
Take a look at the Hyperphysics web page on the Hall Effect.

@Turion: Your calculation looks good.
 

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