Solving a Homogeneous ODE: Step-by-Step Guide

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    Homogeneous Ode
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The discussion centers on solving a homogeneous ordinary differential equation (ODE) given as y' + 4xy - y^2 = 4x^2 - 7. The user has made progress by substituting v = y/x but is unsure of the next steps. Another participant suggests replacing 2x - y with v to simplify the equation further. A third participant hints at a similar problem from their assignment, encouraging the user to refer back to their problem sheets for guidance. Ultimately, the original poster reports that they have figured out the solution.
FeynmanIsMyHero
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Hi,

I'm having trouble with this ODE:

y' + 4xy - y^2 = 4x^2 - 7

=> y' = 4x^2 - 4xy + y^2 - 7
= (2x - y)^2 - 7

=> x(dv/dx) + v = (2x-vx)^2 - 7
= x^2(2-v)^2 - 7


I assume this ODE is of the homogeneous type, so I've substituted v=y/x and gotten thus far, but, what's the next step?
 
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FeynmanIsMyHero said:
Hi,

I'm having trouble with this ODE:

y' + 4xy - y^2 = 4x^2 - 7

=> y' = 4x^2 - 4xy + y^2 - 7
= (2x - y)^2 - 7




Try to replace 2x-y by v and solve for v. .

ehild
 
Hmm this looks exactly like one of the questions on my assignment. Don't know of you are from University of Melbourne but if you are then you are ignoring the explicit instruction that we're supposed to write up the solutions to the assignment independently.

In any case if you are from the same uni as I am then a hint that I can give you w/o actually telling you how to do the question is to go back to the problem sheets. There is a question which requires the same technique.

You are on the right track btw.
 
Last edited:
Thanks, I've figured it out now! :-p
 
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