Solving a Partial Differential Equation

the0
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Homework Statement



Find functions y=y(x) defined on (-∞,0) or (0,+∞) which verify:

xy'+(x2-1)cot(y)=0,
y(x_0{})=y_0{} for x_0{}≠0 and cos(y_0{})≠0

The Attempt at a Solution



I'm really stuck on this one!
Any help will be very much appreciated!
 
Last edited:
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welcome to pf!

hi the0! welcome to pf! :smile:

hint: separation of variables? :wink:
 
Ok, thanks!
So I get:

xy' = (1-2x2)cot(y)



y'tan(y) = (1-2x2)/x

Then how do I go about integrating the left hand side?
 
the0 said:
y'tan(y) = (1-2x2)/x

(where did that 2 come from? :confused:)

easier if you write it with d's …

tan(y) dy = (1-x2)/x dx :smile:
 
I realized that it was that simple right after I posted it haha
and I missed out the 2 in the original statement of the problem, my mistake, sorry about that.
Thanks a lot!
 
I realized that it was that simple right after I posted it haha
and I missed out the 2 in the original statement of the problem, my mistake, sorry about that.
Thanks a lot!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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