Solving a Second-Order Differential Equation with Variable Coefficients

der.physika
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Solve the Differential Equation 2yy\prime\prime+2xy\prime=0

set p=y\prime, and then it becomes case 1 in the textbook

Can someone please help me solve this? It's a night mare
 
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Doesn't that simplify to y=-x?
 
ideasrule said:
Doesn't that simplify to y=-x?

Did you consider the
y\prime that it's not the same as y
 
der.physika said:
Did you consider the y' that it's not the same as y
What's your point? y' is a common factor in the equation you wrote. Did you not post the problem correctly?
der.physika said:
Solve the Differential Equation 2yy\prime+2xy\prime=0

set p=y\prime, and then it becomes case 1 in the textbook
You do realize we don't know what textbook you're using and even less likely to have a copy, right?
 
vela said:
What's your point? y' is a common factor in the equation you wrote. Did you not post the problem correctly?

You do realize we don't know what textbook you're using and even less likely to have a copy, right?

Okay, objection 1 makes no sense... but I'll give you you're right for objection 2.

Here's what the textbook says for case 1:

y\prime=p, y\prime\prime=p\prime\mbox {Dependent variable y missing}
 
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der.physika said:
Okay, objection 1 makes no sense
Really? You don't see how x=-y is a solution to 2yy'+2xy'=2y'(x+y)=0?
 
vela said:
Really? You don't see how x=-y is a solution to 2yy'+2xy'=2y'(x+y)=0?

How did you get that solution besides canceling things out?

Cause, this is like a very annoying class, like what method did you use? Did you use p\equiv{y}\prime
 
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You get that solution by canceling things out. It's not the only solution to the original equation, however.
 
vela said:
You get that solution by canceling things out. It's not the only solution to the original equation, however.

could you possibly do it, by using the substitution I posted?
 
  • #10
I don't see what that substitution buys you. Also, it's not your textbook's case 1 as y appears in the differential equation.
 
  • #11
ok I posted this wrong, i feel stupid

2yy\prime\prime+2xy\prime=0

how do I solve this?

give me a hint maybe?
 
  • #12
I don't know. Maybe someone else here has a suggestion.
 
  • #13
What's the point of the 2's? I would have just canceled them out from the beginning.

(Y*Y'')/Y' = -X

(Y''/Y')(Y) = -X

Set P = Y', then:

(P'/P)Integral(P) = -X

Ok, I'm sorry. This is going nowhere. Given me 24 hours to think about it.
 
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