Solving a Suspended Ball in an Electric Field

AI Thread Summary
To solve for the electric field strength of a suspended ball with a mass of 0.30 kg and a charge of 500 x 10^-4 C, the equation E = F/Q is applied. The user initially struggled with the force triangle diagram but received clarification on the direction of the tension force. After correcting the triangle, they successfully calculated the electric field strength as 1.25 x 10^3 N/C directed to the left. The discussion highlights the importance of accurately representing forces in equilibrium situations. Overall, the interaction led to a clearer understanding of the problem and its solution.
Jabababa
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Homework Statement



a 030 kg ball is suspended in a uniform electric field as shown. If the charge on the ball is 500 x10^-4 C, what is the electric field strength?

Homework Equations



E= F/Q

The Attempt at a Solution



I did this by using the triangle method. draw the forces with a triangle(look at the attachment).
My question is did i draw the triangle right? Does the direction of the Electric field affect my answer?
 

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My question is did i draw the triangle right?
Since the ball is in equilibrium, the forces on it must add to zero.
Look at the direction of the tension force in your triangle.
 
oh my, thank you so much ap123!

I just got the tension force backwards, now it makes much more sense! thank you !
 
Have you worked out the value for the electric field?
 
yes i got 1.25 x10^3 N/C to the left
 

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