Solving a Swing Problem: Finding the Tension

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    Swing Tension
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To solve the swing problem, consider the forces acting on the child sitting on the swing, which include the tension force and the weight force. When the swing is at an angle theta from vertical, the tension can be resolved into x and y components, with the weight acting straight down. The x component of tension relates to the force applied, while the y component must balance the weight of the child. When the swing is vertical, the tension equals the weight, as there is no horizontal force component. Understanding the forces and applying trigonometric principles is essential for calculating tension in both scenarios.
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Swing Problem --

Im looking at a swing problem with a swing at some angle theta from vertical. The swing is massless and a child with weight W sits at the end of the swing. How do i find the tension of the swing? Likewise, when the swing is vertical?

Thanks!:smile:
 
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You should divide the forces into x and y components. What do you think would be the best directions for x and y?
 
I tried, but i got something like the x component of tension being the Force Applied/sin theta and the y component being the weight over sine theta or something like that, but i need to find it in terms of weight and theta.

Thanks for your help!
 
Try with y being into the rope's direction.
What then should forces in that direction equal?
 
ilovephysics123 said:
Im looking at a swing problem with a swing at some angle theta from vertical. The swing is massless and a child with weight W sits at the end of the swing. How do i find the tension of the swing? Likewise, when the swing is vertical?
Thanks!:smile:

Ok, think about this: When the child sits on the swing at rest, what are the forces acting on the child on the swing? At least one contact(tension)force and one non-contact(weight) force. (Is there normal force, if not, then tension force and weight force are equal and opposite right?)

Now the child is in motion. On standard x-y axis, the weight is straight down and tension is \theta from the vertical. Now use your vast knowledge of trigonometry(or even geometry) to find where that angle goes, and set the sum of the forces in the x-direction and y-direction
 
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