Solving a Trig Problem - is this iterative only?

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Homework Statement



Find when this is "0" for the first time:

q(t) = e^{-20t} (5cos(40t) + \frac{5} {2} sin(40t))


Homework Equations





The Attempt at a Solution



0 = e^{-20t} (5cos(40t) + \frac{5} {2}sin(40t))

0 = (5cos(40t) + \frac{5} {2}sin(40t))

cos(40t) = -\frac{1} {2}sin(40t))


Is the best way to solve this perform interations?

Thanks
Sparky
 
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Iterations on what? You've basically solved it. Make that into tan(40t) = -2 and apply arctan. If you don't want a negative number in the argument, you can use the fact that arctan is an odd function.
 
Thanks Kreizhn,

I'm now embarrassed.

this was not seeing the forest for the trees.

I was about to open Excel and try different values of t until I got it to work out.

Thanks
Sparky
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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