Solving a Trigonometry Problem: Uncovering "h

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The discussion centers on solving for the variable "h" in a trigonometry problem involving two triangles and the tangent function. Participants express confusion about the setup and the complexity of the equations derived from the tangent ratios of 30° and 60°. They attempt to relate the lengths of the sides using known values and trigonometric identities but find the algebra challenging. Despite the difficulties, there is encouragement to persist with the problem-solving process, emphasizing that the approach is fundamentally correct. The conversation highlights the common struggle with re-engaging in trigonometry after a long break.
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Homework Statement


[PLAIN]http://img530.imageshack.us/img530/5062/dgsdgsdgs.jpg
what is h??

Homework Equations


tan x = sin x/ cos x
cos x = adj/hyp
sin x = opp/hyp


The Attempt at a Solution


uh I am not even really sure where to start. i haven't done trig in a really really long time. I am guessing you have to use trig. and i set the area under the dotted triangle as x so the entire bottom length would be 100 + X but I am not even sure how that helps.
 
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Add one unknown - length of the leg adjacent to 60° angle. You have two unknowns - h and the leg. Can you express tangents of both angles using these unknowns (and known length 100)?
 
^ no offense but the "clue" you gave was so small that I'm just back where I started...confused...didnt really push me in any particular direction. -_-
tan 30 = h / (100 + x) = sqrt 3 over 3
tan 60 = h / x = sqrt 3?
i don't see how that helps.
i tried solving for h using the one that equals tan 60..that turns out to be x times sqrt 3...i plugged that into the first equation...and that just seems way too complicated. I did this type of question two years ago in HS...i am so sure this question isn't supposed to be this complicated.
 
ooovooos said:
i tried solving for h using the one that equals tan 60..that turns out to be x times sqrt 3...i plugged that into the first equation...and that just seems way too complicated. I did this type of question two years ago in HS...i am so sure this question isn't supposed to be this complicated.

Is this the equation you got?

\frac{x\sqrt{3}}{100 + x} = \frac{\sqrt{3}}{3}

It requires a bit of algebra, but it's not bad.
 
ooovooos said:
i tried solving for h using the one that equals tan 60..that turns out to be x times sqrt 3...i plugged that into the first equation...

You got to two equations in two unknowns, and you are solving them using correct approach. Just don't give up.
 
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Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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