Solving Advanced SHM Problem: Tips & Guidance

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A user seeks guidance on solving an advanced simple harmonic motion (SHM) problem without wanting the direct answer. They share their initial approach, which involves equations related to SHM, and ask for feedback on whether their explanation is sufficient. Another participant requests that images be rotated for better readability. The user agrees to provide a clearer picture and indicates that the discussion will be closed now that it has been moved to the homework section. The focus remains on collaborative problem-solving and clarity in communication.
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I have a homework problem I need help with. I don't want the answer given to me since I know I can answer it with the proper guidance.
How should I approach this problem?

ImageUploadedByPhysics Forums1409893185.944767.jpg


This is what I have so far. How should I approach this? Did I start off right?
ImageUploadedByPhysics Forums1409893621.787673.jpg

Thanks in advanced!
 
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Sorry thought this was the homework section
 
hi there

can you please rotate and repost your images so I don't have to lie down to try and read them :)

cheers
Dave

PS have asked for it to be moved to homework section
 
We have:
x=\alpha \cos{(\omega t-\phi)} \Rightarrow \dot x=-\alpha \omega \sin{(\omega t-\phi)}
Let's take \delta=\omega t-\phi, then we can write:
\sin^2 \delta+\cos^2 \delta=1 \Rightarrow (\frac{\dot x}{\alpha \omega})^2+(\frac{x}{\alpha})^2=1.
Is it enough or I should explain further?
 
Shyan said:
We have:
x=\alpha \cos{(\omega t-\phi)} \Rightarrow \dot x=-\alpha \omega \sin{(\omega t-\phi)}
Let's take \delta=\omega t-\phi, then we can write:
\sin^2 \delta+\cos^2 \delta=1 \Rightarrow (\frac{\dot x}{\alpha \omega})^2+(\frac{x}{\alpha})^2=1.
Is it enough or I should explain further?
Mhmm let me see what I can extrapolate from this. Give me a moment... Thanks btw.
 
davenn said:
hi there

can you please rotate and repost your images so I don't have to lie down to try and read them :)

cheers
Dave

PS have asked for it to be moved to homework section
Okay! I will take a better picture!
 
Since this has been reposted in the HW section, I will close this thread.
 
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