Solving Angle X with Sin(x/2)=1/2 & Tan(x)=sqrt(3)

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To solve for angle x given sin(x/2) = 1/2 and tan(x) = sqrt(3), one can utilize trigonometric identities rather than direct inverse functions. The equation sin(x/2) = 1/2 indicates that x/2 could be 30° or 150°, leading to potential values of x as 60° or 300°. The condition tan(x) = sqrt(3) suggests that x could also be 60° or 240°. By considering both conditions, the valid solutions for x within the range of 0 to 360° are 60° and 300°. Exploring the relationship between these angles and the properties of an equilateral triangle can provide further insights into the problem.
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find the angle x
if its known that:
sin(x/2) = 1/2
tan(x)=sqrt(3)

0<=x<=360
 
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why don't you simply do arcsine and arctan?
 
because the whole point of the question is using trigonometric identities to solve it (believe me i would be happy to do the arctan and get it over with :smile: )
 
Anzas said:
because the whole point of the question is using trigonometric identities to solve it (believe me i would be happy to do the arctan and get it over with :smile: )

You might discover something interesting about the problem though. (It's also worth noting that that there are special angles involved.)
 
i tried playing around with it

sin(x/2) = 1/2
tan(x)=sqrt(3)

i got

tan(x) = sin(x) / cos(x) = sqrt(3)

sin^2(x) / cos^2(x) = 3

but that didn't really lead me anywhere
i thought of ways to convert sin(x/2) to sin(x) with no luck
 
Anzas said:
find the angle x
if its known that:
sin(x/2) = 1/2
tan(x)=sqrt(3)

0<=x<=360

If you don't want to use the inverse trig functions directly then you may want to ponder the equilateral triangle!
 
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