Solving Angular Rotation w/ Constant Acceleration - Emilie

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Emilie is working on a problem involving angular rotation with constant acceleration, where her potter's wheel has an angular acceleration of 2.25 rad/s² and rotates through 60.0 rad in 4 seconds. She initially attempted to calculate the initial angular velocity using the formula a = (ω2 - ω1) / (t2 - t1) but arrived at an incorrect answer of 6 rad/s. The correct approach involves recognizing that the average angular velocity (ω̄) is equal to the change in angle (Δθ) divided by the change in time (Δt), leading to ω̄ = (ω2 + ω1) / 2. This indicates that her misunderstanding stemmed from misapplying the relationship between angular displacement and velocity. Understanding this concept is crucial for solving similar problems accurately.
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I've been trying to do this question in the textbook, but I can't seem to get the answer.

Emilie's potter's whel rotates with a constant 2.25 rad/s^2 angular acceleration. After 4 seconds the wheel has rotated through an angle of 60.0 rad. What was hte angular velocty of the wheel at the beginning of the 4.00 second interval.

I thought I could use a = (w2-w1)/ (t2-t1), but I end up with 6 as my answer, which is incorrect.

Thank you in advance.
 
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Perhaps this thread will help.
 
Ok, I've got it. But why is my method incorrect?
 
~angel~ said:
Ok, I've got it. But why is my method incorrect?

Because:

\omega_2\ne\frac{\Delta \theta}{\Delta t}=15\ rad/s

Actually,

\bar{\omega}=\frac{\omega_2+\omega_1}{2}=\frac{\Delta \theta}{\Delta t}
 
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