Solving arcsin(sin 3π): Step-by-Step Guide

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To solve arcsin(sin 3π), first recognize that sin 3π equals 0. The arcsin function has a restricted range, specifically between -π/2 and π/2, meaning the output must fall within this interval. Therefore, the correct answer to arcsin(0) is 0, not π/2. Understanding the domain of the arcsin function is crucial for determining the correct output value. This clarification emphasizes that while sin 3π equals 0, the arcsin function's constraints dictate the final answer.
cdhotfire
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srry to be a bother but can someone help me on how to do this, it explains it in the book but i don't understand.
Here it is:

arcsin(sin 3(pi))

i would really appreciate ur help, and thxs before hand. :smile:
 
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Do it one step at a time. To what is sin 3(pi) equal?
 
0 right. Is that the awnser, huh?
I was told it was pi/2.
 
You were told? By whom?
 
a friend he said it was pi/2, i guess he was wrong because i see now way of getting that, well for these problems like the one above i just get trig function inside the para and that's the awnser. Can i make that generalization?

oh, and thxs for the help :biggrin:
 
cdhotfire said:
a friend he said it was pi/2, i guess he was wrong because i see now way of getting that, well for these problems like the one above i just get trig function inside the para and that's the awnser. Can i make that generalization?

oh, and thxs for the help :biggrin:

No. What's the domain for the arcsin function? A function only has one possible y (range) for any given value of x (domain).

0 is not the final answer (the quoted post suggests you know that). Instead you have to find a value within the domain of the arcsin function that has a sine of 0.

The variation is if, instead of asking the arcsine, the question asks for all possible values for \theta that have some given value for sine.
 
ooh, ok, thank very much, take care. :smile: :smile:
 
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