Solving Block on Incline Physics Problem

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Maiia
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Can someone tell me if I'm doing this problem right?

Homework Statement


Here is the picture of the problem:
http://i210.photobucket.com/albums/bb23/Kyashii628/block.jpg

In my FBD, I have Fg pointing down, Fgy perpendicular to the incline and pointing down, Fgx parallel to incline pointing down the ramp (to left), kinetic friction pointing up the ramp (to right), and normal force pointing opposite from Fgy.

Homework Equations


Fnet= -ma
fk- Fgx= -ma
u(Fn)= -ma
u(345.0615986)= 648.9664808 -240
u= 1.182397583
 
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Maiia said:
Can someone tell me if I'm doing this problem right?

Homework Statement


Here is the picture of the problem:
http://i210.photobucket.com/albums/bb23/Kyashii628/block.jpg

In my FBD, I have Fg pointing down, Fgy perpendicular to the incline and pointing down, Fgx parallel to incline pointing down the ramp (to left), kinetic friction pointing up the ramp (to right), and normal force pointing opposite from Fgy.
good, but remember in your FBD, that once you resolve Fg into its x and y components, you should 'cross out' the Fg downward force.

Homework Equations


Fnet= -ma
fk- Fgx= -ma
good
u(Fn)= -ma
I'm sure you meant u(Fn) = fk
u(345.0615986)= 648.9664808 -240
you have your mg(sin theta)and mg(cos theta) reversed.
u= 1.182397583
Correct your error and your result should be fine.
 
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