Solving Circuits with Kirchoff's Laws

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The discussion focuses on solving a circuit using Kirchhoff's Laws, with one participant expressing frustration over the length of their solution. They seek a shorter method referenced from a website. Another participant suggests that the current approach requires setting equations to zero to solve for unknowns, indicating that while determinants could be used, they may not offer significant time savings for this particular circuit. The conversation emphasizes the necessity of understanding the equations derived from Kirchhoff's Laws for effective circuit analysis. Ultimately, the consensus is that while there may be various methods, the complexity of the circuit dictates the solution's length.
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http://www.pa.msu.edu/courses/1997spring/PHY232/lectures/kirchoff/examples.html"

how can you solve my circuit (that i attached) using that procedure... in that site.. i saw it last week... that's the shortest way i seen... can you help me.. thankss
 

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Did you learned Kirchoff's laws ? Show your work.
 
yah i learned it... but it is the longest solution... i hate that... i want the shortest method... that i found in that site.. can you solve it using that method?

i put the answer @ my attachment

here is the solution I've learned

@node B
i1 + 12 - i3 = 0
i3 = i1 + i2 that is for eq. 1

@loop abefa
E1 + E2 -15i1 +26i2
40v + 50v -15i1 +26i2
90 + 26i2 / 15i1 eq. 2

@loop bcdeb
-E2 -E3 -26i2 -37i3
-50 -60 -26i2 -37i3
-110 -37i3 / 26i2 eq. 3

that is the my sample solution I've learnd... but it is not finish.. like i said; that is the longest solution... hoping that you understand it...

(sorry bad grammar)
 
You need to set the second two things equal to zero to make them equations. That gives you 3 equations and 3 unknowns -- just solve away. There's not really a quicker way to solve it that I know of, unless you mean using determinants to solve the simultaneous equations. In this circuit, the equations are simple enough that solving with determinants won't save you any time.
 

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