Solving Complex Number Equations: Tips for Beginners | Mathboy20

mathboy20
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Hi I'm fairly new to complex numbers and was yesterday presented with the following assignment.

Find w,z \in \mathbb{C}

w + (1+i)z = -1

(1-i) - z = 1

Any hints on how to solve these equations?

Sincerely Yours

Mathboy20
 
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Systems of linear equations with complex numbers can be solved with the same methods used for real systems, perhaps easiest are matrix methods or Cramer's rule.
 
For example--oh, it is easier to do this:


(1) w + (1+i)z = -1
(2) (1-i) - z = 1

(2) gives z=-i (by adding z-1 to both sides), substitute this into (1) to get

w + (1+i)(-i) = -1
w + -i+1 = -1
w = -2+i

so the final answer is z=-i and w=-2+i
 
You generally solve complex equations the same way you would solve real equations.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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