Solving Conduction Heat Wave in Metal Bar

AI Thread Summary
The discussion centers on solving a problem related to a conduction heat wave in a metal bar, described by the equation T(x,t) = Tmean + Ti sin[2π(0.027t – 3.0x) + Co]. Participants seek clarification on how to determine the amplitude and wavelength of the wave, with the amplitude being directly identified as Ti, which is 2.0 °C. There is confusion regarding the substitution of values for "x" and "t" to find temperature at specific points, emphasizing the need for unit conversion, particularly from millimeters to meters. One participant struggles with obtaining the correct temperature value when substituting given values into the equation, highlighting the importance of accurate unit conversion in calculations. The discussion ultimately clarifies the relationship between the wave equation and the temperature function, aiding in the understanding of the problem.
roam
Messages
1,265
Reaction score
12

Homework Statement



A conduction heat wave is caused to pass through a metal bar of average temperature Tmean = 35.0 °C, altering its temperature sinusoidally with an amplitude of Ti = 2.0 °C. The equation which gives the temperature, T(x,t), of the metal bar at any place x (in meters) inside it at any time t (in seconds) is:

T(x,t) = Tmean + Ti sin[ 2π(0.027t – 3.0x) + Co ]

where Co = 1.0π.

(a) What is the amplitude of the wave? (b) What is the wavelength of the wave?


Homework Equations



  • Speed of sound wave (where B is the bulk modulus and mu p is the pressure): v=\sqrt{\frac{B}{\rho}}
  • Power of sinusoidal wave: P=\frac{1}{2} \mu \omega^2 A^2 v
  • For sound traveling through air:v=(331)\sqrt{1+\frac{T_C}{273}}

  • Wave function for a sinusoidal wave: y=A sin(kx-\omega t)

The Attempt at a Solution



I don't understand how to apprach this problem. For example for part (a), what formula can I use? Also how do I find the temprature using the given equation:

T(x,t) = Tmean + Ti sin[ 2π(0.027t – 3.0x) + Co ]

what values do I need to substitute for "x" and "t"?
 
Last edited:
Physics news on Phys.org
roam said:
Also how do I find the temprature using the given equation:

T(x,t) = Tmean + Ti sin[ 2π(0.027t – 3.0x) + Co ]
Where does it ask you to find the temperature? :confused:
roam said:
what values do I need to substitute for "x" and "t"?
The temperature is different at different positions and different times. To find the temperature at a specific point in space and at a specific time, you would substitute in the position coordinate (x) of that point in space, and the time coordinate t.

Part (a) asks you for the amplitude of the wave. Do you know what amplitude means? Do you know how to find it from a wave equation? For instance, the equation
y=A \sin(kx - \omega t)
represents a wave. What would be the amplitude of that wave?
 
diazona said:
Part (a) asks you for the amplitude of the wave. Do you know what amplitude means? Do you know how to find it from a wave equation? For instance, the equation
y=A \sin(kx - \omega t)
represents a wave. What would be the amplitude of that wave?

"A" represents the amplitude. But how should I find the amplitude in this particular problem? The equation given only describes the temprature not the wave.
 
Well, you know that
y(x,t)=A \sin(kx - \omega t)
represents a wave, right? Do you also accept that
y(x,t) = y_\text{mean} + A \sin(kx - \omega t + \phi)
represents a wave? (How would you find its amplitude?)

If so, what's the problem? The equation
T(x,t) = T_\text{mean} + T_i \sin[2\pi(0.027t - 3.0x) + C_0]
is exactly the same thing, just with different letters.
 
Thanks, I get it now. :smile:

Here's my last question: they further ask "What is the value of T(x,t) when t = 170.0 s, and x = 210.0 mm?"

I simply substituted the given values of "t" and "x" (along with other previously given values) into the equation:

T(x,t) = Tmean + Ti sin[ 2π(0.027t – 3.0x) + Co]

But the value I got was not the correct answer. Why is that? :confused:
 
did u convert into metres?
 
Killeregg said:
did u convert into metres?

40 mm = 0.04 m

37 sin(2 \pi (0.027(130)-3(0.04)+)\pi) = -23.5

But the correct answer must be 33.7! Why??
 
Back
Top