pardesi
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i was solving thsi problem
and attempted it in this manner
consider a length dx of the rod at a distance x from the pivot now
let \theta be the required angle
dx\cos\theta = dm g
dx\sin\theta = m\omega^{2}x\sin\theta
dividing we get \tan\theta = \frac {\omega^{2}x\sin\theta}{g} which is obviously false
and attempted it in this manner
consider a length dx of the rod at a distance x from the pivot now
let \theta be the required angle
dx\cos\theta = dm g
dx\sin\theta = m\omega^{2}x\sin\theta
dividing we get \tan\theta = \frac {\omega^{2}x\sin\theta}{g} which is obviously false