Solving DC Circuits Power Question: 15 Amps, 220 Volts

AI Thread Summary
To solve the drying time for clothes in a dryer that uses 15 Amps at 220 Volts, first calculate the power output, which is 3300 watts (or joules per second). The total mass of water to evaporate is 3 kg (the difference between wet and dry weight). Using the latent heat of vaporization of 2.26 x 10^6 J/kg, the total energy needed is approximately 6.78 million joules. Dividing this energy by the power output gives a drying time of about 34.2 minutes.
Flaneuse
Messages
23
Reaction score
0
DC Circuits -- Power?

I have a physics question I have been working on for quite some time, but have not yet been able to figure out. I am assuming it probably has more to do with unit conversions than with actual calculations, but I am rather stuck... Here is the question:
An electric clothes dryer draws 15 Amps at 220 Volts. If the clothes put into the dryer have a mass of 7 kg when wet and 4 kg when dry, how long does it take to dry the clothes? (Assume all heat energy goes into vaporizing the water; latent heat of vaporization = 2.26 x 10^6 J/kg)


I figured this was probably a question that had to do with power, since I was given current and voltage, so I used the fact that power=(current)(voltage). Since I know an amp is a Coulomb per second and a volt is a joule per Coulomb, I multiplied 15 Coulombs/second and 220 joules/Coulomb to get 3300 joules/second (or watts, but I had a feeling joules per second would be of more use to me).

I am stuck there though, quite unsure of what to do concerning the weight of water and the latent heat of vaporization. The answer is supposed to be 34.2 minutes. Could someone please give me a hand?
 
Physics news on Phys.org


The power used by the dryer is (as you said) = 220Vrms * 15 = 3300J/s

Now how much energy do you need to dry the clothes?
You need to evaporate 3kg (7-4kg) of water.
You are told it takes 2.26MJ/kg

How many Joules?, you have Joules/second, so how many seconds?
 


Thanks! I really appreciate it :].
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top