Solving DRL Logic Problem: Get Help Here!

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A user is seeking help with a DRL logic problem, specifically regarding the orientation of output diodes in their circuit. They initially posted an unclear image, which led to suggestions for clearer communication and better image presentation. Discussions revolve around circuit paths, voltage estimations, and the need for additional resistor values. The user has made progress but is unsure about the functions of specific diodes (D2 and D3) in their circuit. It is advised that they create a separate thread for further inquiries about the transistor logic to attract relevant responses.
Ahmedzica
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Hi Guys,

I'm solving a DRL related problem

https://dl.dropboxusercontent.com/u/49829206/skitch.jpg

I though the output diode were in forward . but I suddenly noticed that it's in reverse .. so I couldn't handle the answer. can anybody help,please?
 
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Your pic is not viewable by the public.
 
oh Sorry ... here is it

https://dl.dropboxusercontent.com/u/49829206/skitch.jpg
 
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Ahmedzica said:
oh Sorry ... here is it

https://dl.dropboxusercontent.com/u/49829206/skitch.jpg

Just as a general note, when you ask someone to do you a favor (like answering a question for you), it's not really a good idea to make it difficult for them (by, for example, posting a picture sideways so that it is very hard to read).
 
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phinds said:
Just as a general note, when you ask someone to do you a favor (like answering a question for you), it's not really a good idea to make it difficult for them (by, for example, posting a picture sideways so that it is very hard to read).

yes you're right .. I'm sorry
 
NascentOxygen said:
Scroll halfway down through this http://site.iugaza.edu.ps/mjouda/files/EXP-3.pdf

I haven't read it, but it looks like they discuss it.

it isn't the same.. as they the anode of the output diode connected to voltage source
 
Ahmedzica said:
it isn't the same.. as they the anode of the output diode connected to voltage source
Ah, so it is. That causes me to conclude you have drawn it incorrectly, as I can see yours not functioning properly with that diode blocking the output. What do your classmates think?


attachment.php?attachmentid=58519.jpg



◗ Where you wrote Vcc - I1R, can you describe the path I takes through your circuit?

◗ For inputs 1 0 0 I'd be inclined to estimate Vx as a little higher than 0.7V to distinguish that condition from some others (such as 0 1 1). Can you account for this?

◗ You gave one resistor a value, do you need to estimate a value for the other resistor, too?

 

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This looks better: http://people.seas.harvard.edu/~jones/es154/lectures/lecture_7/DL_DTL/ls_dl.jpg
 
  • #10
NascentOxygen said:
Ah, so it is. That causes me to conclude you have drawn it incorrectly, as I can see yours not functioning properly with that diode blocking the output. What do your classmates think?


attachment.php?attachmentid=58519.jpg



◗ Where you wrote Vcc - I1R, can you describe the path I takes through your circuit?

◗ For inputs 1 0 0 I'd be inclined to estimate Vx as a little higher than 0.7V to distinguish that condition from some others (such as 0 1 1). Can you account for this?

◗ You gave one resistor a value, do you need to estimate a value for the other resistor, too?


yes that's what I thought.. I solved it as the one right here
http://people.seas.harvard.edu/~jones/es154/lectures/lecture_7/DL_DTL/ls_dl.jpg
 
  • #11
what do you think of this

https://dl.dropboxusercontent.com/u/49829206/Photo%20May%2006%2C%205%2007%2025%20PM.jpg

I've solved it but I can not know what is the function of D2 and D3, could you tell me,please?
 
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  • #12
Ahmedzica said:
what do you think of this

https://dl.dropboxusercontent.com/u/49829206/Photo%20May%2006%2C%205%2007%2025%20PM.jpg

I've solved it but I can not know what is the function of D2 and D3, could you tell me,please?
I don't know what the purpose of D2 is. But as this circuit does not fit under the heading "DRL Logic question" I think you should post it as a separate thread. Other students interested in this transistor logic would not find it under the current header.
 
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