Let It Be
- 45
- 0
1. Trying to understand how to work a given angle into an answer in projectile motion problems.
2. ΔX=ViTf+1/2ATf^2
R=2vi^2sinθcosθ/g
3. Well, I know if you're given say 45° then you would use sin for vertical and cos for horizontal. But beyond that, what are you supposed to do with an angle when given one.
ALSO:
For the first equation, do you substitute Vi for Visinθ or Vicosθ?
2. ΔX=ViTf+1/2ATf^2
R=2vi^2sinθcosθ/g
3. Well, I know if you're given say 45° then you would use sin for vertical and cos for horizontal. But beyond that, what are you supposed to do with an angle when given one.
ALSO:
For the first equation, do you substitute Vi for Visinθ or Vicosθ?