Solving Equations Using Sin/Cos: Projectile Motion

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In projectile motion problems, understanding how to incorporate angles is crucial for accurate calculations. The equations ΔX=ViTf+1/2ATf^2 and R=2vi^2sinθcosθ/g are essential for determining horizontal and vertical components. When given an angle like 45°, sin is used for vertical motion and cos for horizontal motion. The substitution of Vi depends on the definition of θ, requiring clarification on whether to use Visinθ or Vicosθ. Overall, the application of trigonometric functions is key to solving these equations effectively.
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1. Trying to understand how to work a given angle into an answer in projectile motion problems.

2. ΔX=ViTf+1/2ATf^2
R=2vi^2sinθcosθ/g

3. Well, I know if you're given say 45° then you would use sin for vertical and cos for horizontal. But beyond that, what are you supposed to do with an angle when given one.

ALSO:
For the first equation, do you substitute Vi for Visinθ or Vicosθ?
 
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It depends upon how θ is defined ! (Answer to both questions)
 
SammyS said:
It depends upon how θ is defined ! (Answer to both questions)

Can you explain a little more on that?
 
Let It Be said:
Can you explain a little more on that?

Sure.
 

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