Solving "Find k if g(x) is Continuous

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Homework Help Overview

The problem involves determining the value of k for which the piecewise function g(x) is continuous at x = 3. The function is defined as g(x) = x + 3 for x = 3 and g(x) = 2 + √k for x = 3.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss whether g(x) is well-defined and explore the conditions for continuity at x = 3. There is an attempt to equate the left-hand and right-hand limits to find k.

Discussion Status

Some participants have provided guidance on equating the two expressions for continuity, while others express uncertainty about the initial setup and implications of continuity. There is a mix of attempts to clarify the problem and explore reasoning without reaching a consensus.

Contextual Notes

There is a mention of the need to avoid contradictions in the definition of g(x) and the implications of continuity at a specific point. Additionally, some participants suggest external resources for further understanding.

hallowon
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Homework Statement



g(x)={x+3, x[STRIKE]=[/STRIKE]3
{2+[tex]\sqrt{k}[/tex] , x=3

find k if g(x) is continuous

Homework Equations





The Attempt at a Solution



I have no idea how to begin, but drawing the first part on a cartesian plane.
 
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Are you sure g(x) is well defined? Because if it is you just have to get a k that doesn't cause a contradiction...
 


Hi Hallowon
Is the first part not x+3, and x not eual to 3? YA

To say that g(x) is continuous at y=3 is to say that

lim as x goes to 3 = f(3)

In our case the left hand side is equal to x + 3= 3+ 3=6

while the right hand side is equal to 2 + rootk but this must equal the left hand side for it to be continuous so we have

6= 2 + rootk
4=rootk
16=k

Hope this helps. Sorry I had to give solution.haha
 


ahh thank you i didn't event hink to make them equal to one another. Looks like i have a long way to go for continuity -_-
 


Ah your welcome. Its actually not that bad. I haven't really covered it but if you have any futher questions don't hesitate to ask. If you look on you tube they might have something on continuity. It would be much more helpful seeing someone go through it rather than reading from some black and white textbook.
 


Seb97 said:
Hope this helps. Sorry I had to give solution.haha
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Giving out solutions to homework problems is against the guidelines of Physics Forums. Please review the section on Homework Help https://www.physicsforums.com/showthread.php?t=5374".
 
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