Solving for Angle of Vector: Ball Bouncing Problem | Physics Homework Help

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A ball is tossed, bounces off the ground, and rises to a height of 3.10 m before landing 0.70 m away. The vertical velocity (Vy) was calculated as approximately 7.799 m/s, while the horizontal velocity (Vx) was determined to be 0.441 m/s. The angle of the vector was initially calculated using the inverse tangent function but was found to be incorrect. The correct formula for the angle is tan(θ) = Vy/Vx, leading to a revised calculation for the angle. The discussion emphasizes the importance of using the correct relationship between vertical and horizontal components to find the accurate angle.
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Homework Statement



A ball is tossed so that it bounces off the ground, rises to a height of 3.10 m, and then hits the ground again 0.70 m away from the first bounce.

Homework Equations


H= .5(v^2/g) for y velocity.


The Attempt at a Solution


Vy=squareroot of(60.822) Vy= 7.799 m/s
Vx= .70 m/1.59 s= .441 m/s
inversetangent(Vy+Vx)= angle ------ is this correct?

i did the inversetangent and it came out to be about 79.4 degrees. but that wasn't the correct answer :(
 
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your Vx , Vy are correct but the angle is wrong.

\tan(\theta)=\frac{V_y}{V_x}=\frac{7.79}{0.44}
 
thank you! :)
 

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