Solving for Ball Collision: A vs. B Atop a Building

AI Thread Summary
The discussion centers on a physics problem involving two balls: Ball A, dropped from a building, and Ball B, thrown upward from the ground. The key point is that when they collide, Ball A is moving four times faster than Ball B. Participants suggest using kinematic equations to analyze the motion and determine the height at which the collision occurs. The conversation emphasizes the importance of showing work to facilitate assistance in solving the problem. Understanding the paths and speeds of both balls is crucial for finding the solution.
kidia
Messages
65
Reaction score
0
Does anyone can help me on this please?
Ball A is dropped from the top of building at the same instant the ball B is thrown vertically upward from the ground.When the balls collide,they are moving in the same direction,and the speed of A is 4 times that of B.At what fraction of the height of the building does collision occurs?
I will appreciate.
 
Physics news on Phys.org
So, where did you get stuck? Please show us your working so we can help you.
 
Think of ways to express the paths of both balls. Maybe a kinematic equation could help or perhaps the useful K.E. equation... K.E. = \frac{1}{2}mv^2

That should get you started.

Jameson
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top