Solving for coefficient of friction

tep
Messages
2
Reaction score
0
1. a worker can supply a maximum pull of 150 lb on a cart w/c has a handle set at an angle of 40° above the horizontal. what is the coefficient of friction if he can just move a total load of 1500 lb ?



2. μ = Ff/mg



3. so i solved it by 150sin(40) divide by 1500cos(40), but I'm not sure if it is correct... please help :)
 
Physics news on Phys.org
Please show your working and reasoning.
 
my answer is 0.083 but I'm not sure if its correct.
 
That's answer ... please show your working and your reasoning.
Without this information I cannot help you properly.
I don't think you've summed the forces properly but I don't know.

i.e.: you did: 1500cos(40) - how did you decide to do that? What does that figure represent?
Did you draw a free-body diagram? What?
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
Back
Top